- Yesterday, 1:17 am
- Forum: General Forum
- Topic: What’s Ito’s lemma for Poisson process in this function?
- Replies:
**5** - Views:
**404**

Thank you. I have corrected the typo. However, in \(dY_t=Z_{N_t} dN_t\), \(Z_{N_t}\) is a random variable, indicating the random jump size. I think it makes sense to include an expectation w.r.t. \(Z_{N_t} \) in the drift term, as in page 26 of http://people.ucalgary.ca/~aswish/JumpProcesses.pdf ...

- November 18th, 2019, 8:53 am
- Forum: General Forum
- Topic: What’s Ito’s lemma for Poisson process in this function?
- Replies:
**5** - Views:
**404**

Thank you Alan. May I ask one more question? In page 645 of your given file, there is an Ito formula for the compensated compund Poisson process: $$f(Y_t)=f(0)+\int_0^t \!(f(Y_s)-f(Y_s-))(dN_s-\lambda ds)+\lambda \int_0^t \!(f(Y_s)-f(Y_s-))ds$$ where \(dY_t=Z_{N_t} dN_t \) is a compound Poisson proc...

- November 16th, 2019, 10:25 am
- Forum: General Forum
- Topic: What’s Ito’s lemma for Poisson process in this function?
- Replies:
**5** - Views:
**404**

If \(N_t\) is a Poisson process with intensity \(\lambda \),and \(dX_t=\delta dN_t\), \(q_t=-N_t\), then the Ito's lemma for function \(H(X_t)\) should be $$ dH(X_t)=[H(X_t+\delta)-H(X_t)]dN_t$$ For the function \(H(X_t,q_t)\), why it is not something like this? $$ dH(X_t,q_t)=[H(X_t+\delta,q_t)-H...

- October 15th, 2019, 3:10 am
- Forum: Technical Forum
- Topic: Why is Bellman Equation solved by backwards?
- Replies:
**32** - Views:
**4572**

Thank you katastrofa. I think your explanation make sense.

- October 10th, 2019, 1:35 am
- Forum: Technical Forum
- Topic: Is there any stochastic control literature about a linear combination of variables?
- Replies:
**0** - Views:
**1494**

Suppose I have a portfolio of N options and they are affected by M Brownian motions, where M<<N. I hope to maximize the expected return of this portfolio, which is a linear combination of each stock’s return. Then how to formulate the HJB equation? Is there any classical literature/material about th...

- July 24th, 2019, 2:33 am
- Forum: Technical Forum
- Topic: Why is Bellman Equation solved by backwards?
- Replies:
**32** - Views:
**4572**

Thank you Alan. I can understand the option pricing problem. The BS pde must be solved by backwards, only because the terminal condition, i.e., the option pay off, is well defined. The initial option price is unknown(or cannot be difined), so need to be solved. This is not because of the data is non...

- July 23rd, 2019, 1:13 am
- Forum: Technical Forum
- Topic: Why is Bellman Equation solved by backwards?
- Replies:
**32** - Views:
**4572**

Thank you all, but I what I cannot understand is the real reason that Bellman equation is ususally solved by backwards. Can any one give an exmaple in which both intitial and terminal conditions are well defined, but the Bellman equation can only be solved by backwards?

- July 22nd, 2019, 8:30 am
- Forum: Technical Forum
- Topic: Why is Bellman Equation solved by backwards?
- Replies:
**32** - Views:
**4572**

Thank you katstrofa. I aslo think the Bellman equation can be solve by forwards with well defined and NON-stationary data. But that's in contrast to Nicole Bäuerle and Ulrich Rieder' book. I cannot understand why the stationarity of data is related to forward/backward solution.

- July 22nd, 2019, 1:18 am
- Forum: Technical Forum
- Topic: Why is Bellman Equation solved by backwards?
- Replies:
**32** - Views:
**4572**

I cannot make a specific example, because I read that in a book. The followingsa are the images I took from Nicole Bäuerle and Ulrich Rieder' book. Maybe I can rephase the question, if the initial condition is well defined and the data is NON-stationary, can the Bellman equation be solved by forward...

- July 21st, 2019, 3:13 pm
- Forum: Technical Forum
- Topic: Why is Bellman Equation solved by backwards?
- Replies:
**32** - Views:
**4572**

I though Bellman Equation was solved by backwards because the terminal condition is easier to define than the initial condition. Until recently, I read the book Markov decision processes with application to finance by Nicole Bäuerle and Ulrich Rieder. It says ‘Due to the stationarity of the data ho...

- June 1st, 2019, 10:21 am
- Forum: Brainteaser Forum
- Topic: What's the optimal strategy to this food transportation problem?
- Replies:
**3** - Views:
**2281**

The distance between city A and B is 100 km. The total food needs to move from A to B is 3 tons. A transportation team can carry food 1 ton per day and at the same time consumes food 0.25 tons per day. Then how to setup transfer stations between city A nd B to minimize food consumption during tran...

- May 29th, 2019, 12:34 am
- Forum: Numerical Methods Forum
- Topic: How to calibrate an exponential distribution with scale?
- Replies:
**6** - Views:
**2244**

I think the model should work for small-tick-size assets. But for most of other asset types, this model is not applicable directly.

- May 28th, 2019, 1:32 am
- Forum: Numerical Methods Forum
- Topic: How to calibrate an exponential distribution with scale?
- Replies:
**6** - Views:
**2244**

Thank you for your reminding. I confused something here. \(\lambda(\delta)=Aexp(-\kappa\delta) \) is not a pdf. This model is from the paper "High-frequency trading in a limit order book "by MARCO AVELLANEDA and SASHA STOIKOV. \(\lambda(\delta)=Aexp(-\kappa\delta) \) is acutally the exponential a...

- May 27th, 2019, 3:46 am
- Forum: Numerical Methods Forum
- Topic: How to calibrate an exponential distribution with scale?
- Replies:
**6** - Views:
**2244**

I want to fit an exponential arrival rate from my data with below model, a more detail is given in my next post: $$\lambda(\delta)=Aexp(-\kappa\delta) $$ MATLAB can fit an exponential distribution with the following pdf: $$Y(\delta)=\frac{1}\mu exp(-\frac{\delta}\mu) $$ But is there any way to conve...

- May 7th, 2019, 2:12 am
- Forum: Numerical Methods Forum
- Topic: Why the minimum is taken here when its derivative > 0?
- Replies:
**2** - Views:
**2103**

Below are sentensce taken from a paper. "In fact, we are going to prove that $$\forall t\in[0,T],\forall q\in\{-Q,...,Q\},\nu_q(t)\ge e^{-(\alpha Q^2-\eta)(T-t)} $$ If this was not true then there would exist \(\epsilon \gt0\) such that: $$\min_{t,q}e^{-2\eta(T-t)}(v_q(t)-e^{-(\alpha*Q^2-\eta)(T-t)}...

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