Hi, if I can helpLet's try to go back to the original problemIf the equation is the following
^x^x = 2, then the solution is clearly 2^(1/2)If the equation is x^x^x^x^x^x^x^x^x^x^x^x^x^x^x^x^x^x^....until infinity = 2, I will say that there is in theory no solution to the problem.For me,if 0<x<1, it will converge to 1if x=1, the solution is obviously 1if x>1, it will divergeIF it can be helpful