<t>i believe Mike Crowe is who got the closest to the answer to the original question. Actually there are 10 ways to obtain 15 with 3 dices: 3! times (4,5,6) + 3 times (3,6,6) + 1 (5,5,5) = 10. Prob of obtaining sum = 15 out of 3 dices = p = 10/216. n: r.v. of number of ways we have to throw to unti...