<t>2/ is still not clear to me, in this example the Nb options = %Spot Notional/ Spot. The %Spot Notional = weight x variance notional = 1.10E-5 x 1,388 = 0.15268. Let's assume S(T)= 100% then you would get Nb options = 0.15268/ 100% = 0.15268 call.This seems a wrong amount of calls to me, if you do...