If you think about this - you'll realise that theres no way that the function can be unique!

The series converges, but i guess i won't post the answer here so that the others get a chance to work out the solution.

The style of questions you ask made me think that perhaps you were involved with it. I really like all the questions and answers you've posted so far! Very elegant!

Oops sorry forgot about that one. Yes you're right! By the way were you involved with the IMO at all?

The 6x6x6 cube? Sorry which one was that again?

Very nice indeed!! Thanks very much!

I know only one proof. I would definitely be very interested in hearing all the proofs you know! Excellent stuff!

Yes even i've been thinking of posting this for a while now. Its a very nice problem isn't it?

<t>Hi,Heres a nice problem.Let R be a rectangle which is subdivided into smaller rectangles. The smaller rectangles all have one property in common! One of its sides has integral length. Then show that the rectangle R also shares the property that one of its sides has integral length!By integral len...

<t>I haven't thought this through as yet, hopefully if i get some time tonight will try and think about it a bit more, but heres a preliminary try.So let A be a maximal example to your question then i'm guessing that you can always embed an integer hypercube within it? If so then that should lead to...

Hi grantzhong,Actually theres are configurations you are missing. For example 124 which is not allowed in the question asked. I think Zarnywhoop's method is probably the best and most natural way to think about the problem.

<r>Hil,Actually i was trying to think of the generalisation of your problem and decided to do some searching and i came across this book "Computing the continuous discretely" - <URL url="http://math.sfsu.edu/beck/ccd.html">http://math.sfsu.edu/beck/ccd.html</URL> Thought it might interest anyone who...

Excellent stuff!! Gosh that was answered pretty fast!! Well done

Hi,Regarding your question. Check out this previous post http://www.wilmott.com/messageview.cfm? ... adid=36717

Heres a problem for the weekend.Can you pack 53 bricks of dimensions 1x1x4 into a 6x6x6 box? The faces of the bricks are parallel to the faces of the box