<t>QuoteOriginally posted by: pk14I think for your simpler case, MLE only tells you b>=X.Nothing more because the distribution is uniform.I don't get why the MLE tells nothing more, "because the distribution is uniform" ?My thinking was that the probability of drawing the X, which we actually saw be...

<t>Let's try something simpler first :A Uniform distribution extends over [0,b]. I chose 1 point randomly and call it X.Given X, what can I say about b? Answer : (1) b >= X and (2) the best estimate for b, using MLE approach is that b=X.I think the same conclusion results whether you choose 1 point,...

I guess, I found it, myself. It could be done using:Application.CalculateFullRebuild

<t>Manually, I can rebuild the Dependency Tree in Excel using CTRL+ALT+SHIFT+F9 (pressing these 4 keys together from the keyboard).How could I rebuild it automatically from VBA ?(Apart from using the SendKeys command, which might actually work too .. but will interfere in my working on the same PC o...

QuoteOriginally posted by: sriharsha(btw, if you don't mind, which indian bank is this? I was in India for 6 months, so just curious as to which indian banks hire for their trading desks)Got to be ICICI.

<t>Trying to reason this out intuitively, I could think of only one reason:The maximum payoff on a put is capped at K. (upper bound of Max(K-S,0) is K).However, there is no upper bound on the payoff on the call option. Max(S-K,0) can be a very large number (though probabilities will get lower as the...

P(X=0) = 0.50000P(X=1) = 0.16667P(X=2) = 0.08333P(X=3) = 0.05000P(X=4) = 0.20000

<t>One lowly question on c++ .... but have to ask :I encounter the following line of code in c++ :class something className : public baseClassName{....}Question: What could "something" in the above code be?In the code I see, "something" could be some typedef or something declared elsewhere using #de...

QuoteOriginally posted by: INFIDELThis is only true if a,b,c >= 0.well, ya!i should've kept my eyes open."nice" .. withdrawn.

QuoteOriginally posted by: doq, same goes for b and c.This gives three inequalities: , and .Now we add them up and getAs this completes the proof.Perhaps it's still too complicated for a two-liner...nice !

<t>QuoteOriginally posted by: SPMarsInstead I'd rather see the max doesn't occur on the boundary by setting one of the variables as -3/4 and then the problem drops a dimension and we can either use 2-D Lagrange multipliers or work directly. Once this is done we do indeed find the max must be at x=y=...

<t>If we release the first constraint i.e. a,b,c> -3/4 then do we get any relief on the upper bound of 9/10 which applies on the expression of interest. Also, isn't it also true that the lower bound on the expression of interest is -9/10 (with or without the a,b,c>-3/4 constraint) ?If the upper boun...

<t>Well .... this is how our IT guys fixed the problem (this was before MMP posted the Fixed Decimal option solution) : They removed ... i mean, just renamed the entry for HKEY_CURRENT_USER->...->office->excel in the windows registry to a dummy value).Restarting excel, caused the office installer to...

Works great ... thanks for your help.(I too have Excel 2003)