<t>I found this answer on the net Rolling one die, the probability of a 1,2,3,4,5 (i.e., not a 6) is 5/6. Since we assume that the 4 rolls are independent, the probability of 4 rolls, all 1,2,3,4,5, is:P(all 1-5) = 5/6 * 5/6 * 5/6 * 5/6 = 625 / 1296The probability of at least one six is P(at least o...