Turn on switch 1 for a while. Then turn it off and turn on switch 2. Proceed quickly to the adjacent room. 1. Light bulb is off but hot: switch 12. Light bulb is on: switch 23. Light bulb is off and it's cold: switch 3

<t>Hi TomfrN^c is an integer if N and c are positive integers for all positive integer N.If c is not integer, ie. c=a/b where a and b are positive integers and a‚b and b‚1. N^c=N^(a/b)=[N^(1/b)]^a. Since a is a positive integer, for N^c to be integer would require [N^(1/b)] to be positive integer....

<t>Hi Tomfr,You start from right to left, pushing the zero towards the left. Whereas, I was trying to push the zero towards the centre.I have a question. For the second iteration, when you look for the rightmost zero, do you look at N or ((10^K)+1)*N for the rightmost zero since you have already add...

<t>Hi Tomfr,N=2^1999For N, the first and last digit will not be zero and the last digit can only be 2, 4, 6 or 8. I assume that there are some zeros in between the first and last digit of N. N is of the form xxx0…x0x…0xx.L: No. of non zero digits counting from the left of N’ before hitting a zero.R:...

Thanks Aaron.I will bear that in mind when I have the chance to value a FX or IR basket option. I will be careful when it comes to estimating the correlation matrix and the model risk as well.Thank you.

<t>Thanks Aaron.I will try to estimate the correlation matrix and simulate for the equity basket option. You mentioned that for FX, IR or commodity, you will need more complex models. Isn't the simulation similar to the simulation for the equity basket?As for the correlation vega, are you referring ...

<t>Hi Aaron,I can understand the difficulty in obtaining the dependence among the underlyings and the dependence among the underlyings volatilities. What is the general technic that's been used in the industry to price basket option? Is it multivariate Monte Carlo or is it some other methodolgy? Tha...

I have got 21978 as well.

Arroway,I have got one answer as well. It's 3816547290. CK

I have got the same answer as Athletico with the optimal strategy stopping when the winning hits 15 or more. The expected value that I calculated is also about $6.1537. There is no harm playing this game since no money is required to enter the game.CK

If I start with nothing and I play this game whereby I throw a dice as many times as I want. For each throw, if 1 appears I win $1, 2 appears I win $2 ....but if 6 appears I lose all my money. So when is the optimal stopping time and what is the expected winning?

I got the same answer as zerdna. 10 open.Regards,CK

Tomfr, so what is your solution using 6 steps?

HiAnybody would like to give the solution for 5 or 6 steps.

HiI can do it in 8 steps. Is it the minimum? Thanks.