<t>Here G(x,t) = ln(x). Then dG/dt = 0. But we know that x is a function of t, x = f(t). So if we simply substitute G(x,t) = ln(x) = ln(f(t)) = G(f(t), t), then G becomes a function of t. I am having trouble convincing myself that the dependence on t somehow vanishes when you define an intermediate ...