If X is uniformly distributed in 0 and 1, what is E[X|X<B], where B can be viewed as a constant.I am a little confused, here =1 or 1/B ? I feel like it is 1/B, so E[X|X<B]=B/2 .Am I correct?

yes, the answer is :when p<=0.5, ==> 2pwhen p>0.5 ==> 2(1-p)in all, ==> 2* min{p,1-p}

<t>1)For American option, when risk free interest rate increase, will it increase the possibility of early excises?2)For best of two options, you buy one option, which will give you the bestpayoff between two underlying options. For example,for a best put option,two stocks A (A0 =100) and B( A0=100)...

The simplest way is solve: ==> X = 42

QuoteOriginally posted by: LandscapeI don't see how it would be wrong...E[ X | X + Y = 1 ] = 1 - E[ Y | X + Y = 1 ] => E[...] = 1/2is another way of writing it.cool method...

I got E[X]=40 for (d), as following:then get E[X] = 40.Here, the first term is both two keys are pressed correctlythe 2nd term means the first key is pressed correctly, but the second key was wrongthe 3rd terms means both key presses are wrong.Thanks for pointing out mistake.

I was asked this question in an interview from a top wallstreet IB.

<t>Why ' the expected sum is same whether the balls are picked with replacement or without replacement' ?QuoteOriginally posted by: ilikeprobabilityreaverprog, the expected value of the sum computed by twointhebush is as follows. If you were to pick just one ball, what is the expected number? It is ...

<t>I think the answers for random walk and Brownian motion are the same.Define stop time \tau hitting either 3 or -2, Martingale stoping at stopping time is still a martingale.For random walk, Sn is martingale, so E[S_{\tau}] = S_0 = 0 ==> P*.3 + (1-p)(-2) = 0 ==> p=2/5For Brownian motion, W_t is ma...

<t>My answers:1. P = 0.2. Given one point, the other two points must be on the two sides of the diameter which passes the center and the first point. Now we consider only clockwise arrangement of the three points, then the final answer is (1/2)^2 * 3 = 3/4.This is similar question as what's the prob...

Here Cov(X-Y,X+Y) = Cov(X,X) + Cov(X,Y) - Cov(X,Y) - Cov(Y,Y) = 0Is this correct?

Given X, Y ~ N(0,1), E[X|X+Y=1]=?

<t>Part of my course project (simulate a payment system) requires me to write a C++ code to implement following:-----------------Accepts a string (input), judge whether it is a valid currency amount or not.----------I hope you guys can give me suggestions for:(1) What kind of possible input scenario...

From the Amazon customer reviews on this book, looks like this book focused on illustrating the theory, no too much on implementation of the theory. Is this true? What I need to is really practical implementation HJM theory with market data. Thanks.