Sorry - I mistakenly misread the previous line. Thanks

Hi quantyst,How do you get the 2 in: int(2(1-(3/5)/x)dx [3/5,1])?Thanks!

<t>QuoteOriginally posted by: montecristoI dont think so daveangelLet N be the number of throws to get all six numbers. The probleme is about calculating (E(N(N+1)/2)-21) which is greater than ((E(N)²+E(N)/2)-21)MCarreira reminds that E(N)=14.7, so what we are calculating must be greater than 94.395...

let m be the number of average flipsm = (1-p)(1+m) + (1-p)[2p+3p^2+4p^3+...+np^(n-1)+... ]let k = [2p+3p^2+4p^3+...+np^(n-1)]k simplifies to p(2-p)/(1-p)^2which leads us to get m = 1/[p(1-p)]