<t>X is hypergeometric(2, 47, 9).P(X >= 1) = 1 - P(X=0) = 1 - (9 over 0)(47-9 over 2-0)/(47 over 2) = 1 - 38*37/(47*46).That is, the probability to get the flush if we have not yet seen the flop is: [X is hyg(5, 50, 11)]P(X >=3) = 1 - P(X=0) - P(X=1) - P(X=2) = [computer] = 0.06399Step 2:If by "hit ...

<t>Consider only the upper bound, i.e. the lower bound is 0. Denote upper bound by u, and let X be Bin(14, p)Now put H0: p > u, H1: p < uP(Obtain our data or worse under H0) = P(X = 0 | X bin(14, u) = (1 - u)^14 >= 0.05 [If we do not wish to reject] => u = 1 - 0.05^(1/14).That is, we reject H0 at 95...

<r>Wrote a long post about gibbs sampling but discarded it. Probably this is what you need:<URL url="http://www.mathworks.se/products/sysid/index.htmlAnd">http://www.mathworks.se/products/sysid/index.htmlAnd</URL> this should give you the right keywords to search for:<URL url="http://sstl.cee.illino...

a,b,c > 0:First equation => a = 1 and b or c is equal to 0.{c = 0 => b = sqrt(2012) which is not integer} => only pos sol is a = 1, b = 0, c = 2012/2.Observations for negative integers:1. b is positive implies c is negative.2. a is odd and b is even.

<t>1. What is the expected time until we hit first head? Answer: 2.2. What is the probability that you will get head again and thus have your first HH? Answer: 1/2. (If fail, we will start from zero)3. Expected time to hit HH must therefore be 3/(1/2) = 6.Or in mathematics:t_0 = first time to hit HE...

<t>Maybe I did not read the previous answers carefully enough but it seems to me that you answer the question "Guess which floor I hid the egg on, if you guess higher you lose a point'.Therefore, model of the egg falling:We know that impact speed (and thus the probability that the egg breaks) increa...

Extension of problem:Solve for biased coin, i.e. when P(heads) = p, P(tails) = q.

<t>Hmm, perhaps not a very good suggestion but at least it is working and repeating...big-transpose -> (A(BC))^T = (BC)A = BCA -> shift ->B^-1(BCA)B = CAB -> small-transpose ->(CA)^TB = ACB -> shift ->A^-1(ACB)A = CBA -> big-transpose ->(C(BA))^T = (BA)C = BAC edit: "Transpose" is a bad name, as you...

<t>Expected length of the path including the first head is 2.By extending this path by one step we will of course have a path that is 3 steps long. Half of these paths will include the first double-head and half will not, thus on average we need two of these paths to reach our goal, i.e. the expecte...

<t>P(R<r) = P(X<r & X>a)/P(X>a) = P(X<r)*I(r>a)/(1-Phi(a))=> f_R = f_x(r)/(1-Phi(a))*I(r>a)integrate from a to inf x*f_X = exp(-a^2/2)/sqrt(2*pi)i.e.E R = exp(-a^2/2)/(sqrt(2*pi)*(1-Phi(a))Tested it; seems to be right. Edit: Should have refreshed the page before posting (thus seeing bwarrens pos...

<t>QuoteOriginally posted by: Traden4AlphaQuoteOriginally posted by: LandscapeDisney Land (LA) is about 1/50th of Disney World (Orlando) which is about 1.4 times the size of Manhattan (1/3 water included) and less than 1/10th of London.The cheapness of sending someone into GEO (really like the word ...

I was thinking, if I put all 20 liters in one pot instead of 1 liter I won't have to go refill it every time it vaporizes. I don't know an awful lot about anything, Wiki does, but yes I am a landscape artist.Space_elevator

<t>Disney Land (LA) is about 1/50th of Disney World (Orlando) which is about 1.4 times the size of Manhattan (1/3 water included) and less than 1/10th of London.The cheapness of sending someone into GEO (really like the word and idea, thanks!) was surprising, so checked and found that1. I failed to ...

<t>The average weight for males is 76-83 and females 54-64, lets say then that the average weight is 50 (assuming kids and elderly compensate the rest)Assuming humans have roughly the same density as water this give us that one person is 50 liters.With 7 billion people that's 350 million cubic meter...