Interesting...Following this logic any number but zero will equal 1. However, with all due my respect....the statement is erronous - if you take out the imaginary number and find a proof...now this will be a real proof!

:-)So... which step is the bogus one ?Looks an interesting book, btw

Visual complex analysis?Does that have drop down menus that do all the hard thinking for you?I have to get a copy.QuoteOriginally posted by: genki:-)So... which step is the bogus one ?Looks an interesting book, btw

- EscapeArtist999
**Posts:**1620**Joined:**

the usual alws for exponents don't hold with complex numbers - it has to do with selecting an analytic branch for the complex logarithm... basically you are saying that two different branches of the complex log are the same... when they are not.

QuoteOriginally posted by: genkiWe can similarly 'show' that e=1 without the use of log:e=e^1=e^{1}=e^{(2pi*i)/(2pi*i)}={e^(2pi*i)}^{1/(2pi*i)}=1^{1/(2pi*i)}=1.

NYT - Math Expert Wins Wealth, if Accepts

QuoteOriginally posted by: ExSanNYT - Math Expert Wins Wealth, if AcceptsWhat is wrong with Grigori Perelman? Is he lost in a sphere?

Mathematician's anger over his unread 500-page proof

GZIP: On