[$]\frac{d \,\mbox{Number}}{d \,\mbox{Anything}}=0[$]

I often explain vega via

[$]\frac{\partial \, \mbox{Area of a circle}}{\partial \pi}=r^2[$]

[$]\frac{\partial \, \mbox{Area of a circle}}{\partial \pi}=r^2[$]

- Cuchulainn
**Posts:**62126**Joined:****Location:**Amsterdam-
**Contact:**

[$]\frac{\partial n!}{ \partial n} = (n-1)![$]

thus

[$]\frac{\partial n!}{ \partial (n-1)!} = n[$]

thus

[$]\frac{\partial n!}{ \partial (n-1)!} = n[$]

Last edited by Cuchulainn on February 20th, 2020, 9:24 pm, edited 3 times in total.

- katastrofa
**Posts:**9213**Joined:****Location:**Alpha Centauri

Haben Sie Zahl Schmerzen?

- Cuchulainn
**Posts:**62126**Joined:****Location:**Amsterdam-
**Contact:**

Yes, carnval.Haben Sie Zahl Schmerzen?

I initially learned Dutch from such songs + ads.

www.youtube.com/watch?v=EfOgwRV8sGg

www.youtube.com/watch?v=ChU4gAS3NcE

- Cuchulainn
**Posts:**62126**Joined:****Location:**Amsterdam-
**Contact:**

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

[$]e^5 = 148.413[$]

That was in Stephen King's original draft. But his editor thought it too geeky.

- katastrofa
**Posts:**9213**Joined:****Location:**Alpha Centauri

Mein Deutch ich von Geothe gelernt habe. Oder Meister Yoda...Yes, carnval.Haben Sie Zahl Schmerzen?

I initially learned Dutch from such songs + ads.

www.youtube.com/watch?v=EfOgwRV8sGg

www.youtube.com/watch?v=ChU4gAS3NcE

A small glass of local wine today, and some Martini tomorrow (30m+)

- Cuchulainn
**Posts:**62126**Joined:****Location:**Amsterdam-
**Contact:**

Stoopid question: who is SK?That was in Stephen King's original draft. But his editor thought it too geeky.

Wait - you are in the Canary Islands? Not to be confused with Canary Wharf...Mein Deutch ich von Geothe gelernt habe. Oder Meister Yoda...Yes, carnval.Haben Sie Zahl Schmerzen?

I initially learned Dutch from such songs + ads.

www.youtube.com/watch?v=EfOgwRV8sGg

www.youtube.com/watch?v=ChU4gAS3NcE

A small glass of local wine today, and some Martini tomorrow (30m+)

- katastrofa
**Posts:**9213**Joined:****Location:**Alpha Centauri

Sí, Señor Visitando al diablo.

- Cuchulainn
**Posts:**62126**Joined:****Location:**Amsterdam-
**Contact:**

Got it! Penny drops.That was in Stephen King's original draft. But his editor thought it too geeky.

[$]\frac{\partial^2 \, \mbox{Area of a circle}}{\partial \pi \partial x}=ab[$]I often explain vega via

[$]\frac{\partial \, \mbox{Area of a circle}}{\partial \pi}=r^2[$]

this because a circle moved along the x axis is observed to be an ellipse due to length contraction, so we have the well unknown circle equation

[$]\frac{\partial^2 \, \mbox{Area of a circle}}{\partial \pi \partial t}-\frac{\partial^2 \, \mbox{Area of a circle}}{\partial \pi \partial x}=r^2-ab[$]

or more interesting

[$]\frac{\partial \, \mbox{Area of a circle}}{\partial t}-\frac{\partial \, \mbox{Area of a circle}}{ \partial x}=\pi r^2-\pi ab[$]

where a and b functions of v

and do we also get:?

[$]\frac{\partial \, \mbox{Area of a circle}}{\partial t}-\nabla \mbox{Area of a circle} =\pi r^2-\pi ab[$]

more complex under acceleration.

GZIP: On