SERVING THE QUANTITATIVE FINANCE COMMUNITY

Paul
Posts: 10775
Joined: July 20th, 2001, 3:28 pm

$\frac{d \,\mbox{Number}}{d \,\mbox{Anything}}=0$

Paul
Posts: 10775
Joined: July 20th, 2001, 3:28 pm

I often explain vega via

$\frac{\partial \, \mbox{Area of a circle}}{\partial \pi}=r^2$

Cuchulainn
Posts: 62126
Joined: July 16th, 2004, 7:38 am
Location: Amsterdam
Contact:

$\frac{\partial n!}{ \partial n} = (n-1)!$

thus

$\frac{\partial n!}{ \partial (n-1)!} = n$
Last edited by Cuchulainn on February 20th, 2020, 9:24 pm, edited 3 times in total.

katastrofa
Posts: 9213
Joined: August 16th, 2007, 5:36 am
Location: Alpha Centauri

Haben Sie Zahl Schmerzen?

Cuchulainn
Posts: 62126
Joined: July 16th, 2004, 7:38 am
Location: Amsterdam
Contact:

Haben Sie Zahl Schmerzen?
Yes, carnval.
I initially learned Dutch from such songs + ads.

Cuchulainn
Posts: 62126
Joined: July 16th, 2004, 7:38 am
Location: Amsterdam
Contact:

$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$
$e^5 = 148.413$

Paul
Posts: 10775
Joined: July 20th, 2001, 3:28 pm

That was in Stephen King's original draft. But his editor thought it too geeky.

katastrofa
Posts: 9213
Joined: August 16th, 2007, 5:36 am
Location: Alpha Centauri

Haben Sie Zahl Schmerzen?
Yes, carnval.
I initially learned Dutch from such songs + ads.

Mein Deutch ich von Geothe gelernt habe. Oder Meister Yoda...
A small glass of local wine today, and some Martini tomorrow (30m+)
Attachments

Cuchulainn
Posts: 62126
Joined: July 16th, 2004, 7:38 am
Location: Amsterdam
Contact:

That was in Stephen King's original draft. But his editor thought it too geeky.
Stoopid question: who is SK?

Paul
Posts: 10775
Joined: July 20th, 2001, 3:28 pm

Idea for a TV game show: "What's My Bubble?"

katastrofa
Posts: 9213
Joined: August 16th, 2007, 5:36 am
Location: Alpha Centauri

Nitrogen

bearish
Posts: 5535
Joined: February 3rd, 2011, 2:19 pm

Haben Sie Zahl Schmerzen?
Yes, carnval.
I initially learned Dutch from such songs + ads.

Mein Deutch ich von Geothe gelernt habe. Oder Meister Yoda...
A small glass of local wine today, and some Martini tomorrow (30m+)
Wait - you are in the Canary Islands?  Not to be confused with Canary Wharf...

katastrofa
Posts: 9213
Joined: August 16th, 2007, 5:36 am
Location: Alpha Centauri

Sí, Señor Visitando al diablo.

Cuchulainn
Posts: 62126
Joined: July 16th, 2004, 7:38 am
Location: Amsterdam
Contact:

That was in Stephen King's original draft. But his editor thought it too geeky.
Got it! Penny drops.

Collector
Posts: 4613
Joined: August 21st, 2001, 12:37 pm

I often explain vega via

$\frac{\partial \, \mbox{Area of a circle}}{\partial \pi}=r^2$
$\frac{\partial^2 \, \mbox{Area of a circle}}{\partial \pi \partial x}=ab$

this because a circle moved along the x axis is observed to be an ellipse due to length contraction, so we have the well unknown circle equation

$\frac{\partial^2 \, \mbox{Area of a circle}}{\partial \pi \partial t}-\frac{\partial^2 \, \mbox{Area of a circle}}{\partial \pi \partial x}=r^2-ab$

or more interesting

$\frac{\partial \, \mbox{Area of a circle}}{\partial t}-\frac{\partial \, \mbox{Area of a circle}}{ \partial x}=\pi r^2-\pi ab$

where a and b functions of v

and do we also get:?

$\frac{\partial \, \mbox{Area of a circle}}{\partial t}-\nabla \mbox{Area of a circle} =\pi r^2-\pi ab$

more complex under acceleration.

Wilmott.com has been "Serving the Quantitative Finance Community" since 2001. Continued...

 JOBS BOARD

Looking for a quant job, risk, algo trading,...? Browse jobs here...

GZIP: On