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outrun
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Re: I can't solve this ...

April 24th, 2017, 7:33 pm

Now I see one more! 
I was waiting for you to say that!
 
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outrun
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Re: I can't solve this ...

April 24th, 2017, 7:35 pm

What else is there to do while queuing for bread other than to criticise American mathematics education?

(There are at least five.)
Croissants?
 
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Cuchulainn
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Re: I can't solve this ...

April 24th, 2017, 7:47 pm

Now I see one more! 
I was waiting for you to say that!
It was Paul who put me up to it LOL where's triangle #5? 
 
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Traden4Alpha
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Re: I can't solve this ...

April 24th, 2017, 8:13 pm

Now I see one more! 
I was waiting for you to say that!
It was Paul who put me up to it LOL where's triangle #5? 
I see: upper big gray, lower big gray, lower left small bounded by the perpendicular, lower right medium-sized by the perpendicular, tiny lower left corner tiny formed by a segment of the blue line intersecting the purple one.

Note: there may be several more in the intersections of the lines and the chart-junk hexagonal texture but the JPG is too messy to clearly delineate them.
 
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Cuchulainn
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Re: I can't solve this ...

April 24th, 2017, 8:23 pm

I was waiting for you to say that!
It was Paul who put me up to it LOL where's triangle #5? 
I see: upper big gray, lower big gray, lower left small bounded by the perpendicular, lower right medium-sized by the perpendicular, tiny lower left corner tiny formed by a segment of the blue line intersecting the purple one.

Note: there may be several more in the intersections of the lines and the chart-junk hexagonal texture but the JPG is too messy to clearly delineate them.
This is the way many software projects run into problems, even before 1 line of code is written. 
 
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Traden4Alpha
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Re: I can't solve this ...

April 24th, 2017, 8:32 pm

It was Paul who put me up to it LOL where's triangle #5? 
I see: upper big gray, lower big gray, lower left small bounded by the perpendicular, lower right medium-sized by the perpendicular, tiny lower left corner tiny formed by a segment of the blue line intersecting the purple one.

Note: there may be several more in the intersections of the lines and the chart-junk hexagonal texture but the JPG is too messy to clearly delineate them.
This is the way many software projects run into problems, even before 1 line of code is written. 
Indeed!

Moreover, many software project specifications are like that triangle -- they specify piece-wise doable constraints or goals that are actually mutually impossible.
 
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outrun
Posts: 4573
Joined: January 1st, 1970, 12:00 am

Re: I can't solve this ...

April 24th, 2017, 8:33 pm

It was Paul who put me up to it LOL where's triangle #5? 
I see: upper big gray, lower big gray, lower left small bounded by the perpendicular, lower right medium-sized by the perpendicular, tiny lower left corner tiny formed by a segment of the blue line intersecting the purple one.

Note: there may be several more in the intersections of the lines and the chart-junk hexagonal texture but the JPG is too messy to clearly delineate them.
This is the way many software projects run into problems, even before 1 line of code is written. 
Yes. "I think the specs are pretty clear, let's run it past T4A as a formality and start burning the budget!"
 
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Cuchulainn
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Re: I can't solve this ...

April 25th, 2017, 10:38 am

What's the area of this triangle?
Image
which one? There's 3 of them!
I take it back! There are NO (zero) triangles in this diagram.
 
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outrun
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Re: I can't solve this ...

April 25th, 2017, 10:42 am

What's the area of this triangle?
Image
which one? There's 3 of them!
I take it back! There are NO (zero) triangles in this diagram.
What's a "zero triangle"? Something like a zero bond?
 
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Cuchulainn
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Re: I can't solve this ...

April 25th, 2017, 11:03 am

which one? There's 3 of them!
I take it back! There are NO (zero) triangles in this diagram.
What's a "zero triangle"? Something like a zero bond?
Notice the plural. The set of triangles here is the empty set.
So, where's the triangle? Hoeveel driehoeken zijn er?

It would be better to give the link to the source article..
 
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Traden4Alpha
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Re: I can't solve this ...

April 25th, 2017, 11:37 am

I take it back! There are NO (zero) triangles in this diagram.
What's a "zero triangle"? Something like a zero bond?
Notice the plural. The set of triangles here is the empty set.
So, where's the triangle? Hoeveel driehoeken zijn er?

It would be better to give the link to the source article..
Oh no! The Irish are speaking Dutch again! This can't be good!

P.S. The triangle dimensions are in hexadecimal so all is OK!
 
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Traden4Alpha
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Re: I can't solve this ...

April 25th, 2017, 11:47 am

Note that if one decides to compute the area of the triangle as a*b/2 where a and b are the short and long sides of the triangle (with theta being the narrow angle between the hypotenuse and long side), then one might be derive the answer as:

a = 10*sin(theta)
b = 10*cos(theta)

theta = asin(6/b)

a = 10*sin(asin(6/b)) = 10*6/b

area = a*b/2 = 10*6/2 = 30

(Of course the numerical values of a, b, and theta would be complex but why is that a showstopper?)
 
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Cuchulainn
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Re: I can't solve this ...

April 25th, 2017, 12:26 pm

 
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outrun
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Re: I can't solve this ...

April 25th, 2017, 12:43 pm

I take it back! There are NO (zero) triangles in this diagram.
What's a "zero triangle"? Something like a zero bond?
Notice the plural. The set of triangles here is the empty set.
So, where's the triangle? Hoeveel driehoeken zijn er?

It would be better to give the link to the source article..
never! That would be cheating, it's exactly the same as those school assignment post in Student "Can someone for me motivate (in at most 3 pages) that the American put price is not always the same as the European put price?"
(ps, the solution you found on the internet is fake russian news)
Last edited by outrun on April 25th, 2017, 12:45 pm, edited 1 time in total.
 
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Traden4Alpha
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Re: I can't solve this ...

April 25th, 2017, 12:44 pm

Interesting

But those answers concluding that the triangle does not exist requiring adding constraints to the problem that are not in the problem definition such as the numbers being base 10 and the dimensions of the triangles being real numbers.

If the given numbers are not base 10 (i.e., the numbers are base 12 or higher), the answer is 6*10/2 in that base.

If the problem is not artificially constrained to real numbers, the answer is 6*10/2.

The problem states that the triangles exist and have the stated dimensional and angular properties. Given the constraint of the triangle's existence, it's up to the student to find an interpretation of the specifications that leads to an answer. In essence, some of the "unknowns" in this problem are the base of the two given values and choice of number system for the nuisance variables.

The solution exists but not in base 10 && real numbers.