You mean, like high-school geometry?Can someone explain why this is of any interest at all?!

- Cuchulainn
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You mean, like high-school geometry?Can someone explain why this is of any interest at all?!

http://www.datasimfinancial.com

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

- Cuchulainn
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I am still waiting on a solution from Paul and T4A

OK what about [$]x^2 = 2[$]. Find x. All of them.

OK what about [$]x^2 = 2[$]. Find x. All of them.

Last edited by Cuchulainn on May 18th, 2017, 6:39 pm, edited 1 time in total.

http://www.datasimfinancial.com

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

Have you been at the Brennivín again? Or did you fall down a volcano? We are worried about you.

- Traden4Alpha
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Is y in degrees, gradians, radians, mils, arc-seconds, revolutions, .... or what?I am still waiting on a solution from Paul and T4A

Spacecraft have crashed over this issue!

[$]x^2 = 2[$]OK what about [$]x^2 = 2[$]. Find x.

^ there it is!

Would you prefer -1.41421356237...?

It's a trick question. Notice the different typeface. So it's just after "Find"I am still waiting on a solution from Paul and T4A

OK what about [$]x^2 = 2[$]. Find x.

- Traden4Alpha
**Posts:**23951**Joined:**

Damn! But it's worse than that. There's no EOL character or even a semicolon after the "x" so the find command is still incomplete.It's a trick question. Notice the different typeface. So it's just after "Find"I am still waiting on a solution from Paul and T4A

OK what about [$]x^2 = 2[$]. Find x.

Back to primary school for us!

- Cuchulainn
**Posts:**60757**Joined:****Location:**Amsterdam-
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Ah! Back to multiple choice questions!Damn! But it's worse than that. There's no EOL character or even a semicolon after the "x" so the find command is still incomplete.It's a trick question. Notice the different typeface. So it's just after "Find"I am still waiting on a solution from Paul and T4A

OK what about [$]x^2 = 2[$]. Find x.

You are going off on a tangent. Focus.

I like "it's" here.

Last edited by Cuchulainn on May 18th, 2017, 7:10 pm, edited 2 times in total.

http://www.datasimfinancial.com

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

- Cuchulainn
**Posts:**60757**Joined:****Location:**Amsterdam-
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It is possible to write it using [$]\arcsin[$] if you prefer.Back to primary school for us!

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

an old jokeDamn! But it's worse than that. There's no EOL character or even a semicolon after the "x" so the find command is still incomplete.I am still waiting on a solution from Paul and T4A

OK what about [$]x^2 = 2[$]. Find x.

- Traden4Alpha
**Posts:**23951**Joined:**

Ppauper already has the best answer for this specific problem as stated by this specific problem poster.Ah! Back to multiple choice questions!Damn! But it's worse than that. There's no EOL character or even a semicolon after the "x" so the find command is still incomplete.It's a trick question. Notice the different typeface. So it's just after "Find"

You are going off on a tangent. Focus.

I like "it's" here.

I did ponder building an analog computing version using a circle 0.2 meters in radius but that's when I realized that y could not be both an angle and a distance. Hence, units are a showstopper!

It's also interesting that if eccentricity is a variable, there's only a miniscule range of values (about [$]-3.8 < \varepsilon < +2.1[$]) where there's a unique solution. The whole system seems very non-robust to the broader parametric space but then I assume the numbers were carefully cherry-picked to lead the student to a particular approach to a numerical solution rather than a more general solution on the entire set of possible values of x and eccentricity.

- Cuchulainn
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But it took you 5 noisy posts to get this stage.

The problem has nothing to do with units!!! It's a matematical (not engineering) problem that has 0, 1 or many solutions. That's the nub.(read Banach, for example).

*Ppauper already has the best answer for this specific problem as stated by this specific problem poster.*

How did you get to this conclusion? "best" in what sense? BTW ppauper gave two possible solutions.

Sadly, you have killed this thread before it even got off the ground.

I*t's also interesting that if eccentricity is a variable, there's only a miniscule range of values (about **−3.8<ε<+2.1−3.8<ε<+2.1*

) where there's a unique solution. The whole system seems very non-robust to the broader parametric space but then I assume the numbers were carefully cherry-picked to lead the student to a particular approach to a numerical solution rather than a more general solution on the entire set of possible values of x and eccentricity.

No kidding, Sherlock.

The problem has nothing to do with units!!! It's a matematical (not engineering) problem that has 0, 1 or many solutions. That's the nub.(read Banach, for example).

How did you get to this conclusion? "best" in what sense? BTW ppauper gave two possible solutions.

Sadly, you have killed this thread before it even got off the ground.

I

) where there's a unique solution. The whole system seems very non-robust to the broader parametric space but then I assume the numbers were carefully cherry-picked to lead the student to a particular approach to a numerical solution rather than a more general solution on the entire set of possible values of x and eccentricity.

No kidding, Sherlock.

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

Five seconds with pencil and paper (and most of that time spent finding the pencil and paper) or half a second in your head, and you can sketch the problem and see what's happening. Great if this were a forum for twelve-year olds.

But I was waiting for the twist...and it never came. Compare and contrast the "Russian," "Arctan," "Cards," etc.

But I was waiting for the twist...and it never came. Compare and contrast the "Russian," "Arctan," "Cards," etc.

- Traden4Alpha
**Posts:**23951**Joined:**

Sorry!But it took you 5 noisy posts to get this stage.

The problem has nothing to do with units!!! It's a matematical (not engineering) problem that has 0, 1 or many solutions. That's the nub.(read Banach, for example).

Ppauper already has the best answer for this specific problem as stated by this specific problem poster.

How did you get to this conclusion? "best" in what sense? BTW ppauper gave two possible solutions.

Sadly, you have killed this thread before it even got off the ground.

But your thread title seemed to implicitly encourage tangents and no where was it stated that this was strictly a math problem. I often use my pocket calculator for brainteasers and it gives different answers for sin(y) depending on the angle mode.

----

What direction did you want this thread to go before my eccentricity collided with yours?

- Cuchulainn
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You need to read up on conic sections (you cannot have negative eccentricity as you claim) and there is an analytical formula for y for all values of the eccentricity.

Please correct me if I have misunderstood your post.

The fixed point solutions is iterative and it does converge slowly ... check out Bessel's solution to Kepler's problem you will find a better exact solution.

*But your thread title seemed to implicitly encourage tangents and no where was it stated that this was strictly a math problem. *

Then ask me to clarify if something is not clear. I did indeed not mention that it was Kepler's equation..

Please correct me if I have misunderstood your post.

The fixed point solutions is iterative and it does converge slowly ... check out Bessel's solution to Kepler's problem you will find a better exact solution.

Then ask me to clarify if something is not clear. I did indeed not mention that it was Kepler's equation..

http://www.datasim.nl

Approach your problem from the right end and begin with the answers. Then one day, perhaps you will find the final question..

R. van Gulik

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