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Cuchulainn
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Joined: July 16th, 2004, 7:38 am
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I hope he's not doing it on NASA' s time.
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http://www.datasim.nl

Every Time We Teach a Child Something, We Keep Him from Inventing It Himself
Jean Piaget

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Joined: August 21st, 2001, 12:37 pm

I hope he's not doing it on NASA' s time.
second best to going to the dark side of the moon must be star shade what about option Geek-Greeks origami ?

Cuchulainn
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Joined: July 16th, 2004, 7:38 am
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Those CAD orgamis evolve into CAM sheet metal.
http://www.datasimfinancial.com
http://www.datasim.nl

Every Time We Teach a Child Something, We Keep Him from Inventing It Himself
Jean Piaget

Paul
Posts: 10418
Joined: July 20th, 2001, 3:28 pm

Are we all agreed the answer is e? (pi wasn’t an option.)

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Joined: August 21st, 2001, 12:37 pm

yes e and the more general solution $e^5$

trackstar
Posts: 27269
Joined: August 28th, 2008, 1:53 pm

Are we all agreed the answer is e? (pi wasn’t an option.)
Alright.  And ordered some books too.

Robert Harbin - author page on Amazon

Robert J. Lang - author page on Amazon

Such - RL is the NASA engineer in one of the previous videos and not only has he developed relevant folding designs for space craft materiel, he left NASA in the early 2000s to see if he could make a living doing origami. Wonderful entrepreneurial streak there.

And here from my art supply box - origami paper from Kyoto circa 1997.
origamipaper.JPG
Probably all of us know how to make cranes and small inflatable boxes, but there is so much more...!

Cuchulainn
Posts: 61518
Joined: July 16th, 2004, 7:38 am
Location: Amsterdam
Contact:

yes e and the more general solution $e^5$
Brilliant induction step.
http://www.datasimfinancial.com
http://www.datasim.nl

Every Time We Teach a Child Something, We Keep Him from Inventing It Himself
Jean Piaget

neauveq
Posts: 10
Joined: May 28th, 2018, 10:25 pm

Are we all agreed the answer is e? (pi wasn’t an option.)
It made sense to me. In each of the columns the middle square represents the union of both the upper and lower squares of that column less the common elements they share. For the unknown square, look at the first square in that column and look for any of its elements that do not appear in the middle square. These will be the common elements of both the first square and the unknown third square. Second, look for any elements in the middle square that do not appear in the first square. These will be the unique elements of the third square. Add the first and second sets together and you get the square represented by option e.