Re: Optimal solution please
Posted: February 5th, 2019, 8:24 pm
I hope he's not doing it on NASA' s time.
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second best to going to the dark side of the moon must be star shade what about option Geek-Greeks origami ?I hope he's not doing it on NASA' s time.
Alright. And ordered some books too.Are we all agreed the answer is e? (pi wasn’t an option.)
Brilliant induction step.yes e and the more general solution \(e^5\)
It made sense to me. In each of the columns the middle square represents the union of both the upper and lower squares of that column less the common elements they share. For the unknown square, look at the first square in that column and look for any of its elements that do not appear in the middle square. These will be the common elements of both the first square and the unknown third square. Second, look for any elements in the middle square that do not appear in the first square. These will be the unique elements of the third square. Add the first and second sets together and you get the square represented by option e.Are we all agreed the answer is e? (pi wasn’t an option.)