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Cuchulainn
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Re: x?

August 5th, 2020, 10:32 am

Hold yer hosses, reduce the scope to 2d first and then review, Check against Green's formula prove things.

https://en.wikipedia.org/wiki/Green%27s_identities

BTW how does it work if I has mixed derivatives? [$]\partial_{xy}u[$].
 
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katastrofa
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Re: x?

August 5th, 2020, 12:06 pm

I suspect it's something to do with [$]\frac{d^n}{dx^n} x^n = n![$], but I don't see how it gives the above.
[$]n[$] is an integer? BTW have you sussed out fractional calculus.
Yes, n is an integer. As for the fractional calculus, we've decided to model those equations fully numerically in the end, but playing with them a bit gave in an idea of the parameter ranges for different system regimes. (Mathematics isn't the native tongue of my collaborators, so it didn't make sense to push that - they are agent-based experts though.)
 
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Cuchulainn
Posts: 20252
Joined: July 16th, 2004, 7:38 am
Location: 20, 000

Re: x?

August 5th, 2020, 1:49 pm

I suspect it's something to do with [$]\frac{d^n}{dx^n} x^n = n![$], but I don't see how it gives the above.
[$]n[$] is an integer? BTW have you sussed out fractional calculus.
Yes, n is an integer. As for the fractional calculus, we've decided to model those equations fully numerically in the end, but playing with them a bit gave in an idea of the parameter ranges for different system regimes. (Mathematics isn't the native tongue of my collaborators, so it didn't make sense to push that - they are agent-based experts though.)
Very wise
si fueris Romae, Romano vivito more; si fueris alibi, vivito sicut ibi
 
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Collector
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Re: x?

August 5th, 2020, 2:45 pm

\(\sqrt{MMCCCXXXVII}\approx 48.34\) ?
 
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Cuchulainn
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Re: x?

August 5th, 2020, 3:54 pm

\(\sqrt{MMCCCXXXVII}\approx 48.34\) ?
Know you know why the Romans never put a man on the Moon.

remember [$]e^5[$]?
 
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Re: x?

August 5th, 2020, 4:42 pm

\(\sqrt{MMCCCXXXVII}\approx 48.34\) ?
Know you know why the Romans never put a man on the Moon.

remember [$]e^5[$]?
? Roman to me.
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