April 6th, 2005, 8:29 pm
Is there a trick in this question?denote A, B and C the children from each of the 3 couples, and let 1 and 0 parameetrize their gender.then you have the following five possibilities,A0 + B1, A1 + B0, C1 and C0 do not get married,C0 + B1, B0 + C0, A1 and A0 do not get married,C0 + A1, A1 + C0, B1 and B0 do not get married,plus the two possibilities mentioned by Aaron.
Last edited by
alexandreC on April 5th, 2005, 10:00 pm, edited 1 time in total.