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pierrelefou
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Joined: July 10th, 2007, 8:00 am

lognormal distribution

September 6th, 2007, 9:03 am

I have a simple questionsuppose S is a process that follow a lognormal distribution of mean 0 and volatilite sigthen, does S follow this equadiff: dS/S=sigma*dW ??? thank you
 
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sorensen
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Joined: September 13th, 2006, 6:49 am

lognormal distribution

September 6th, 2007, 9:57 am

yes,where dW is a Wiener process, i.e. dW = sqrt(dt) * epsilon,and epsilon is taken from a normal distribution with mean = 0, std dev = 1.
 
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Joined: October 26th, 2005, 2:08 pm

lognormal distribution

September 7th, 2007, 5:27 pm

not accurate.the log normal distribution is defined for random variable. if a process follows lognormal that means that it is so for each t and it is not means that the process can be represented as a SDE solution. On the other hand if you SDE, dS/S=sigma*dW then its solution has lognormal distribution. There exist explicit form of a linear equation and taking log you will arrive at the Gaussian distributed function/
 
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Dileep
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Joined: August 12th, 2006, 11:03 pm

lognormal distribution

September 13th, 2007, 5:14 am

Why cant a random variable be a solution to SDE? SDE's have random variables as solutions right? Why isnt this equivalence true both ways?
 
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lognormal distribution

September 13th, 2007, 10:22 am

You probably meant a random function. If you have a deterministic function then it probably is not a solution a linear deterministic differential equation. Several years ago I tried the Hi square test t to check hypothesis regarding geometric SDE. Note that test regarding with constant coefficients linear SDE easy could be reduced to test Gaussian distribution and independence of increments. Gaussian distribution evidence say was 50%-50% independence was much worse.
 
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manolom
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lognormal distribution

September 17th, 2007, 10:30 am

QuoteOriginally posted by: pierrelefouI have a simple questionsuppose S is a process that follow a lognormal distribution of mean 0 and volatilite sigthen, does S follow this equadiff: dS/S=sigma*dW ??? thank youSaying that S follows a lognormal distr. is equivalent to say that log(S) follows a normal distr. This doesn't imply that S must satisfy the equation above. Anyway the reverse is true: if S follows dS/S = mu dt + sigma dWt => S(t) = S(0) * exp{(mu - 0.5*sigma^2)*t + sigma*Wt} is lognormal.
 
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jimmy
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Joined: January 17th, 2002, 1:43 pm

lognormal distribution

September 24th, 2007, 8:31 am

<< lognormal distribution of mean 0 and volatility sig >>means dlnS = -0.5*sigma^2*t+sigma*dWor (if you apply ITO with f = exp)dS/S = sigma*dW