September 29th, 2010, 2:12 pm
p^2-1=(p+1)*(p-1)The terms on the right side are 2 consecutive even numbers. So one is a multiple of 2 and the other is a multiple of 4. Moreover one of them is also a multiple of 3. (one of 3 consecutive numbers is a multiple of 3 and "p" is prime by definition). So (p^2-1) is a multiple of 2*3*4=24