<t>Hi Vanubis1,In the 2nd equation of two players, you said thatP(A/H)=1/2*0+1/2*(1-P(A/H))Because after A tossed a H, if B tosses a T, it's over for A and if B tosses a H, it's 1-P(B/H) and P(B/H)=P(A/H)Should P(A/H)=1/2*0+1/2*P(A/HH)=1/2*0+1/2*P(B/H)=1/2*0+(1-P(A/H)), where P(B/H)=1-P(A/H)? Thanks...