<t>Sorry Traden4, think of the simplistic n=2 , k=4 case, there is only 1 way, but your formula gives 2 . The hole lies in that : If we define a 1-for-1-row 1-for-1 -column pattern a 'basis'(so, n filling in n^2 ), a final qualified arrangement ( k for n^2) a pattern, then certain pattern can possib...