Good day all!
We know that the delta of a long ATM call option must be around +0.5.
The at-the-moneyness means that the current stock price S equals the strike price K, which means the ln(S/K) in the Black-Scholes formula for d1 becomes ZERO. All well there.
In order for N(d1) to be 0.5, d1 should be ZERO (from the standard normal distribution). We already know that ln(S/K) is ZERO. Therefore, the numerator and the denominator in d1 become (r + 0.5 * sigma^2) * T and sigma * sqrt(T) respectively.
I used risk free rate r = 5% (annualized), sigma = 0.8% (annualized), and T = 0.25 years, but really my question is for any values (except T = ZERO) that can be substituted in the formula for d1. In this specific case, d1 computes to ~3.16 and N(d1) therefore is close to 1 (0.99).
I am lost as to why N(d1) doesn't compute to anywhere close to 0.5, given this is an ATM call option. Thanks for educating.