February 28th, 2005, 2:33 pm
Hi babolat,For 2) Map back the Y's to to ti's the default time of the ith issuer. using tj = Fj^(-1)[N(Yj)]with Fj being the cdf of an exponential distribution with parameter h ie. F(x)= 1- e^(-hx).Then the default time tj = -1/h ln (1- N(Yj))Doubts:1) Are u assuming that the hazard rate is constant throughout the life of CDS?2) What IF the hazard rate is not constant throughout and is constant only during certain periods of the life? Then F(x) is expressed in another way ?...... F(x) = 1 - exp( Summation (h(i)*x)) -Correct me if i'm wrong.....In such a case, how do we define the default time tj ?3) For: tj = Fj^(-1)[N(Yj)] If hazard rate is not constant, how do we calculate Fj^(-1) ?
Last edited by
annlim on February 28th, 2005, 11:00 pm, edited 1 time in total.