June 3rd, 2006, 7:07 am
Well, it has a positive probability of going out-of-the-money too. So the question really is, why is the time value always positive for a call option whether it is in-the-money or out-of-the-money?The standard proof uses put-call parity, c - p = S - Xe^(-rT) > S - X => c > S - X. This already tells us that the answer has nothing to do with the nature of the underlying process because put-call parity is independent of that.What is the intuitive reason then?QuoteOriginally posted by: csaI think you meant that it is never optimal to exercise an American option before expiration when the underlying asset does not pay a dividend. The reason for this is that, even if the option is deep in-the-money, then someone should be willing to pay for that option given that value (Stock Price - Strike Price) plus time value (and positive probability of getting deeper into the money). Hence, neglecting transactions costs, it will always demand a higher price rather than just exercising it as (Stock Price - Strike Price).