February 6th, 2012, 2:00 am
EDIT Sorry my indicator variables are positive when there is a lose and negative when there is a profit. I don't know why I did it that way but I don't really wanna go through and change everything.Let me answer your question by first showing you the rigorous way to do the problem you know how to do. Basically the issue I have with your solution is that there isn't really an a priori reason to fit a quadratic. (I mean it makes sense to suspect that you would need a quadratic since second order moments are involved but there isn't really a rigorous justification.)In your 2 asset example there are fundamentally 4 (actually 3 due to symmetry) quantities involved. Probability that only asset 1 loses, probability and 1 and 2 lose, etc.p_1, p_12, p_2, p_0The last one being the probability neither loses. In principle p_1, and p_2 could be different but the way you stated your problem it seems like you're assuming they're the same.The random variables we're working with are X_1 and X_2: kind of indicator variables that can be 1 or -1 the former representing loss and the latter profit.What is the correlation given by? Just compute the Assuming q is the probability a particular asset loses, irrespective of what the other does, and a symmetry between X_1 and X_2 we have (after a bit of algebra)Since we're dealing with probability we also knowp_12 + p_1 + p_2 + p_0 = p_12 + 2*p_1 +p_0 = 1We also have the law of total probability.p_12 +p_1 = qSo we have a system of 3 equations and 3 unknowns.Solving this for p_12 we getp_12 = q (c + q - c q)You'll notice that this can be negative, for some choices of q and c. It's possible that's because I made algebra mistake, but more likely I think it just indicates that some choices of c are incompatible with some choices of q. For example if c = -1, then actually q HAS to be 1/2 just due to symmetry. Every time there is one asset that is up and one down and by observing that labeling them 1 and 2 is arbitrary you notice that only 1/2 makes sense for q (p_12 is negative if q<1/2, and I'm guessing p_0 is negative if q>1/2).So.....if you have three assets, you would do the same thing as I did except the variables would be p_0, p_1,p_2,p_3, p_12, p_23,p_13,p_{123} so if you assume symmetries again then variables would become p_{non at a time}, p_{one at a time}, p_{two at a time}, p_{three at a time}. So now you'd get a 4x4 system. So for the case you asked about you'd need to solve a 6x6 system of equations.
Last edited by
KajetanSikorski on February 5th, 2012, 11:00 pm, edited 1 time in total.