August 27th, 2003, 12:45 pm
Let n be the number of observations, s be the square root of the sum of the residuals squared divided by n-2, m be the mean of the independent variables, v be the variance of the independent variables and a be the estimated intercept. Then a*[(1 + m^2/v)/n]^-0.5/s has a t distribution with n-2 degrees of freedom under the standard least squares assumptions. So the standard error is s*[(1+m^2/v)/n]^0.5.