September 15th, 2012, 9:53 am
QuoteOriginally posted by: MarsWhen changing numeraire you will only change the drift (Girsanov theorem). So euro risk neutral will be dS / S = mu dt + \sigma dW' where W' is a brownian under euro risk neutral measure and mu is what we try to find.The cross term is then : S/ N rho sigma eta dt and we have mu = q - rho sigma etaI do understand that Girsanov says the dynamics of S in the euro RN measure will be dS / S = mu dt + \sigma dW', but somehow my step-by-step derivation doesn't quite fit:* Let S be the dollar asset price, S^e the euro asset price and X = S/S^e the exchange rate* Under Q^$ assume dS/S = r_$ dt + \sigma dW^$, and dX/X = (r_$ - r_e) dt + \eta dZ, with (dW)(dZ) = \rho dt* By Girsanov under Q^e we must have dS^e/S^e = r_e + \sigma dW^e [Eq. A]* We are looking for the dynamics of S under Q^e. By Girsanov this should have the form: dS/S = \mu dt + \sigma dW'* By Ito+Girsanov, under Q^e: d(1/X) / (1/X) = (r_e - r_$) dt - \eta dZ^e* By Ito: dS^e = d(S * 1/X ) = dS/X + Sd(1/X) + (dS)(d1/X) = ... = S^e * [ (\mu + r_e - r_$ - \rho \sigma \eta) dt + \sigma dW' + \eta dZ^e ] [Eq. B]Matching Eq. A and B does produce the correct drift \mu = r_$ + \rho \sigma \etaBUT we also get: \sigma dW^e = \sigma dW' + \eta dZ^e which is impossible...?e.
Last edited by
eiriamjh on September 14th, 2012, 10:00 pm, edited 1 time in total.