June 24th, 2013, 7:57 am
Consider only the upper bound, i.e. the lower bound is 0. Denote upper bound by u, and let X be Bin(14, p)Now put H0: p > u, H1: p < uP(Obtain our data or worse under H0) = P(X = 0 | X bin(14, u) = (1 - u)^14 >= 0.05 [If we do not wish to reject] => u = 1 - 0.05^(1/14).That is, we reject H0 at 95% for values of u less than 1 - 0.05^(1/14) ~= 0.1926.While there is now lower bound on p, if it were larger than 0.1926 then our observed data would be more unusual than 1/20.I.e. our confidence interval is [0, 0.1926]